Question

What is the answer to this question?

What does ix^2 + ix + i = 0 equal when ”i” is the imaginary number?

Answer 1

`x = (i √(3) - 1) / 2`

Explanation:

1. Factor out the imaginary number "i" from the trinomial. This leaves you with:

x^2 + x + 1 = 0

2. From here you need to complete the square and solve for x, which should give you the above answer once simplified.

3. If you wanted to check the answer you can plug it back into the equation to see if you get 0.