Answer:
(3,4)
Explanation:
This system is already setup for linear combination/elimination (don't know what your class calls it).
The reason I say this is because if you add the equations together the variable y will be eliminated giving you a chance to solve for x.
Let's do that:
x+y=7
2x-y=2
--------------Add.
3x =9
Divide both sides by 3:
x =3
Using one of the equations (doesn't matter; you choose) along with x=3 we can find y.
I choose x+y=7 with x=3.
x+y=7 with x=3:
3+y=7
Subtract 3 on both sides:
y=7-3
Simplify:
y=4
The solution is (x,y)=(3,4).
Let's check our solution by plugging it in:
x+y=7
3+4=7
7=7 is true.
2x-y=2
2(3)-4=2
6-4=2
2=2 is true.
Since both equations are true for (x,y)=(3,4), then (3,4) is definitely a solution.
So we have solution confirmation.