Answer:
c. 48.67% ± 8.16%
Explanation:
The proportion is:
p = 73 / 150 = 0.4867
The margin of error is:
ME = z √(p (1 − p) / n)
where z is the critical value, p is the proportion, and n is the sample size.
For a 95% confidence interval, z ≈ 2.
ME = 2 √(0.4867 (1 − 0.4867) / 150)
ME = 0.0816
So the proportion is 48.67% ± 8.16%.