Question

What are the coordinates of y' after a dilation of 3/2 about the origin?

The coordinates are y(0,-2)​

Answer 1

Y'(0, -3)

Explanation:

Dilation about the origin multiplies every coordinate.

Y' = (3/2)Y = (3/2)(0, -2) = (0·3/2, -2·3/2) = (0, -3)