Answer:
values of q are q=0,-9,5/6
Option B is correct
Explanation:
We need to solve the equation:
2q(q+9)^2(6q-5)=0
We will be using zero factor polynomial i,e if ab=0 then a=0 and b=0
so, 2q(q+9)^2(6q-5)=0
2q =0, (q+9)^2 =0 and (6q-5)=0
Finding values of q
2q = 0 => q=0
(q+9)^2 =0 => taking square root
q+9 = 0
q = -9
(6q-5)=0 => 6q-5=0
6q = 5
q = 5/6
So, values of q are q=0,-9,5/6
Option B is correct