Question

Please answer the attached question by selecting of the the given answers.

Answer 1

`Perimeter\,\,of \,\,triangle =(3x^2+7x+21)/(3x^2)` so, Option D is correct.

Explanation:

Perimeter of triangle = Sum of all sides

Perimeter of triangle = a+ b+ c

a= 1/3x, b= x+2/x and c = 7/x^2

`Perimeter\,\,of\,\,triangle =(1)/(3x)+(x+2)/(x)+(7)/(x^2)`

LCM of 3x, x and x^2 : 3x^2

`Perimeter\,\,of\,\,triangle =(x+3x(x+2)+7(3))/(3x^2)\\Perimeter\,\,of \,\,triangle =(x+3x^2+6x+21)/(3x^2)\\Perimeter\,\,of\,\,triangle =(3x^2+7x+21)/(3x^2)`

So,
`Perimeter\,\,of\,\,triangle =(3x^2+7x+21)/(3x^2)` so, Option D is correct.

Answer 2

The correct answer is option D. [3x² + 7x + 21]/3x²

Explanation:

Perimeter of a triangle = sum of all sides

To find the perimeter of triangle

Here sides are,

7/x² , 1/3x and (x + 2)/x

Perimeter = 7/x² + 1/3x + (x + 2)/x

Here LCM = 3x²

Perimeter = (7 * 3)/3x² + (1 * x)/3x² + (x + 2)3x/3x²

= [21 + x + 3x² +6x]/3x²

= [3x² + 7x + 21]/3x²

The correct answer is option D. [3x² + 7x + 21]/3x²