Question

14. Find the real-number solutions to the equation p3 - 4p2 = 0

Answer 1

p=0 or p=4

Explanation:

first simplify the equation

p^3-4p^2=0

p(p^2-4p)=0

p(p-4)(p-0)=0( factorise p^2-4p)

p=0 p=0. p-4=0,p=4

therefore,p=0 or p=4