1.9k views
2 votes
which of the following equations depicts a balanced equation, Na2CO3+2HCl=2NaCl+CO2+H2O, NaCO3+HCl=2NaCl+CO2+1H2O, 2Na2CO3+3HCl=3NaCl+2CO2+H2O or Na2CO3+HCl=NaCl+CO2+h2O??

2 Answers

4 votes

Step-by-step explanation:

The first one is balanced equation

User SiberianGuy
by
6.9k points
4 votes

Answer:


Na_2CO_3+2HCl \Rightarrow 2NaCl+CO_2+H_2O

Option A is the Answer

Step-by-step explanation:

Balancing is making the number of atoms of each element same on both the sides (reactant and product side).

To find the number of atoms of each element we multiply coefficient × subscript

For example
5 Ca_1 Cl_2 contains

5 × 1 = 5 , Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example
3Ca_3 (P_1 O_4 )_2 we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So 3 × 3 = 9, Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present.

A)


Na_2 CO_3+2HCl>2NaCl+CO_2+H_2 O

Reactant Side # of atoms of each element Product Side

2 Na 2

1 C 1

3 O 3

2 H 2

2 Cl 2

Balanced!!!!

B)


NaCO_3+HCl=2NaCl+CO_2+1H_2O

(Chemical formula given for Sodium carbonate is not correct)

Na2CO3 is the correct formula

C)


2Na_2CO_3+3HCl=3NaCl+2CO_2+H_2O

(Not balanced correctly)

Reactant Side # of atoms of each element Product Side

4 Na 3

2 C 2

6 O 5

3 H 2

3 Cl 3

Not same on both the sides

Hence UnBalanced

D)


Na_2CO_3+HCl=NaCl+CO_2+h_2O??

Unbalanced

User RobbZ
by
7.8k points