Answer:
A. p = -4, p = 2.
Explanation:
p^2 + 2p - 8 = 0
Using the quadratic formula;
p = [-2 +/- √(2^2 - 4*1*-8)] / 2
= (-2 +/- √36) / 2
= (-2 +/- 6) / 2
= 4/2 , -8/2
= 2, -4.
A
Given
p² + 2p - 8 = 0 ← in standard form
with a = 1, b = 2, c = - 8
Using the quadratic formula to solve for p
p = ( - 2 ± / 2
= ( - 2 ± / 2
= ( - 2 ± ) / 2
p = = = - 4
p = = = 2
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