Answer:
Option A is correct
Explanation:
The given equation is
h = -16t^2+6t+4
When the ball will hit the ground, height h = 0
Putting value of h = 0
0 = -16t^2+6t+4
Now solving to find the value of t
=> -16t^2+6t+4 = 0
Multiply with -1
16t^2-6t-4=0
Using quadratic formula to find value of t

a= 16, b= -6 and c= -4
Putting values,

Since time cannot be negative, so t = 0.721 or 0.72
So, Option A is correct