Answer:
Option A is correct
Explanation:
The given equation is
h = -16t^2+6t+4
When the ball will hit the ground, height h = 0
Putting value of h = 0
0 = -16t^2+6t+4
Now solving to find the value of t
=> -16t^2+6t+4 = 0
Multiply with -1
16t^2-6t-4=0
Using quadratic formula to find value of t
![x=(-b\pm√(b^2-4ac))/(2a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ty88pbafyv5o23b2f4dpdb7fqtzb1mmwac.png)
a= 16, b= -6 and c= -4
Putting values,
![t=(-(-6)\pm√((-6)^2-4(16)(-4)))/(2(16))\\t=(6\pm√(36+256))/(32)\\t=(6\pm√(292))/(32)\\t=(6\pm17.08)/(32)\\t=(6+17.08)/(32) \,\,and\,\, t=(6-17.08)/(32)\\t=0.721\,\,and\,\, t=-0.34](https://img.qammunity.org/2020/formulas/mathematics/high-school/supwg1ofh5fuiw8v7xou0ymzzw8tdi4ier.png)
Since time cannot be negative, so t = 0.721 or 0.72
So, Option A is correct