Question

A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 6.60 ft from the mirror on the left wall and 14.1 ft from the mirror on the right wall.

Answer 1

The distances from the person to the first three images seen in the left-hand mirror are 6.60 ft, 13.2 ft, and 19.8 ft.

Step-by-step explanation:

To find the distances from the person to the first three images seen in the left-hand mirror, we can use the law of reflection. The distance from the person to the mirror on the left wall is 6.60 ft, and the distance from the person to the mirror on the right wall is 14.1 ft. Since the mirrors are parallel, the images formed will be equidistant from the respective mirrors.

Using the formula for the distance to the image formed by a plane mirror (distance to the mirror = distance to the image), the distances from the person to the first three images seen in the left-hand mirror will be 6.60 ft, 13.2 ft, and 19.8 ft.

Answer 2

Answer:13.2,41.4,82.8 ft

Step-by-step explanation:

Given Person is 6.60 ft from the left hand side mirror

Since the focal length of plane mirror is infinity therefore image and object are equidistant from mirror

Distance of first image on left mirror is

`d_1=6.6+6.6=13.2 ft`

i.e. image is 13.2 ft away from object

Second image

Now the right mirror forms the image of object at distance of 14.1 ft right from right mirror so its image is formed in left mirror at a distance of 34.8 from left mirror

so image distance from person is

`d_2=34.8+6.6=41.4 ft`

Third image now form image of second image is formed on right mirror at a distance of 55.5 right from right mirror

and its mirror image is formed on left mirror at a distance of 76.2 left

from left mirror

`d_3=76.2+6.6=82.8 ft`