124k views
5 votes
Solve 81^x = 27^^^x + 2.

A. x = 1
B. x = 2
C. x = 5
D. x = 6

User Soliz
by
5.9k points

2 Answers

1 vote

Answer:

x=6

Explanation:

81^x=27^(x+2)

3^4x=3^3(x+2)

4x=3(x+2)

4x=3x+6

x=6

User Puj
by
6.3k points
5 votes

For this case we must solve the following equation:


81 ^ x = 27^(x + 2)

We rewrite:


81 = 3 ^ 4\\27 = 3 ^ 3

Then, replacing:


3^(4x) = 3^(3 (x + 2))

For the bases to be equal then it must be fulfilled that:


4x = 3 (x + 2)\\4x = 3x + 6\\4x-3x = 6\\x = 6

Answer:


x = 6

Option D

User Megi
by
5.8k points