Answer:
5600 square feet is the area.
Explanation:
Perimeter will be = 300 feet
Length of the fence enclosure must be at least 80 feet.
Width of the fence enclosure must be at least 40 feet.
Let x be the length and y be the width of the court.
We get following constraints:
![x \geq 80](https://img.qammunity.org/2020/formulas/mathematics/high-school/qxi7n2jqqzbn5xcul7br4jck0lpm6rnhmj.png)
![y \geq 40](https://img.qammunity.org/2020/formulas/mathematics/high-school/1mk9mob9cxh9j3rehyf7lin7sy2j8blk2m.png)
If we calculate the area, we get
![xy \geq3200](https://img.qammunity.org/2020/formulas/mathematics/high-school/ahoi4qrss34e1is4mrp44p0zdy8yywpcii.png)
And for the perimeter we get:
⇒
![x+y= 150](https://img.qammunity.org/2020/formulas/mathematics/high-school/vylpskk2ldwt0kmfpw35laaa19zyqvbbvd.png)
Now look at the graph attached, we get point (80,70) as the possible solution.
So, the maximum area occurs when the dimensions are 80 feet by 70 feet.