Question

50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below.

2N20 + 302 - 2N204

Answer 1

Limiting reactant : O₂

Mass of N₂O₄ produced = 95.83 g

Further explanation

Given

50g nitrous oxide

50g oxygen

Reaction

2N20 + 302 - 2N204

Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

`\tt =(50)/(44)=1.136`

mol O₂ :

`\tt =(50)/(32)=1.5625`

2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136 1.5625

1.0416 1.5625 1.0416

0.0944 0 1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

`\tt =mol* MW=1.0416* 92=95.83~g`