Question

use the heisenberg uncertainty principle to calculate the uncertainity in meters in the position of 0.68g and traveling at a velocity of 0.85 m/s. assume the uncertainity in meters in the position of a helium atom if the uncertaunty in the velocity is 0.1 m/s

Answer 1

7.7439×10⁻³¹ m

Step-by-step explanation:

The expression for Heisenberg uncertainty principle is:

`\Delta x* \Delta v=\frac {h}{4* \pi* m}`

Where m is the mass of the microscopic particle

h is the Planks constant

Δx is the uncertainty in the position

Δv is the uncertainty in the velocity

Given:

mass = 0.68 g = 0.68×10⁻³ kg

Δv = 0.1 m/s

Δx= ?

Applying the above formula as:

`\Delta x* 0.1=\frac {6.62* 10^(-34)}{4* \frac {22}{7}* 0.68* 10^(-3)}`

Δx = 7.7439×10⁻³¹ m