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Omar and Caleb each had a repair made on their cars. The initial cost of each repair is $1,000. Omar and

Caleb each have two coupons. Each of them uses both of his coupons toward the cost of the repair. One
coupon is for $80 off the repair cost. The other coupon is for 15% off the repair cost. Omar and Caleb use their
coupons in a different order, as shown below.
Omar uses the $80 off the repair cost coupon first. He then uses the 15% off the repair cost coupon on
the remaining balance.
Caleb uses the 15% off the repair cost coupon first. He then uses the $80 off the repair cost coupon on
the remaining balance.
Who paid the least amount of money for his car repair and how much less did he pay?

User HyperioN
by
4.6k points

1 Answer

3 votes

Answer:

Caleb paid less than Omar by $12.

Explanation:

The initial cost of each repair is $1,000.

One coupon is for $80 off the repair cost. The other coupon is for 15% off the repair cost.

Case 1:

Omar uses the $80 off the repair cost coupon first. He then uses the 15% off the repair cost coupon on the remaining balance.

Step 1:
1000-80=920

Step 2:
920-(0.15*920)=782 dollars

Case 2:

Caleb uses the 15% off the repair cost coupon first. He then uses the $80 off the repair cost coupon on the remaining balance.

Step 1:
1000-(0.15*1000)=850

Step 2:
850-80=770 dollars

Now, comparing the values we can see that Caleb paid less.

He paid less by
782-770=12 dollars.

User Onionjake
by
6.0k points