Question

A solar panel measures 0.57 m by 1.3 m. In direct sunlight, the panel delivers 6.6 A at 6 V. If the intensity of sunlight is 300 W/m2, what is the efficiency, as a percentage, of the solar panel in converting solar energy into electrical energy?

Answer 1

efficiency of solar panel is 18%

Step-by-step explanation:

Energy received by the sunlight is given as

`Power = intensity * area`

here we know the dimensions of the plate as

`L = 0.57 m`

`W = 1.3 m`

now we have

`Area = (0.57)(1.3) m^2`

`A = 0.741 m^2`

now the power received by the sun light is given as

`P_1 = 0.741(300) = 222.3 W`

now the output power due to solar panel is given as

`P_(out) = V i`

`P_(out) = (6.6 A)(6 V)`

`P_(out) = 39.6 Watt`

now the efficiency is given as

`\eta = (P_(out))/(P_(in))`

`\eta = (39.6)/(222.3)`

`\eta = 0.18`