Question

3y2 - 2x - 12 if x =-1, y=3

Answer 1

17

Explanation:

To evaluate the expression substitute x = - 1 and y = 3 into it

3(- 3)² - 2(- 1) - 12

= 3 × 9 + 2 - 12 = 27 + 2 - 12 = 29 - 12 = 17

Answer 2

`\text{Hey there!}`

`3\text{y}^2-2\text{x}- 12, \text{ if x = -1  \& y = 3}`

`\text{Your equation is now:\ }3(3)^2 - (-1) - 12`

`\text{You can solve this by doing PEMDAS (Parentheses, Exponents, Multiplication}\\\text{Division, Addition, Subtraction), There's other methods too!}`

`\text{We can eliminate \bf{Parentheses}}\text{ because we don't have any in here.}\\\text{Check for \bf{Exponents}}\text{ we have it, so we can use that first to solve.}`

`3^2 = 3*3 = \bf{9}`

`\text{New equation: 3(9) - 2(-1) - 12}`

`\text{Thirdly, check to see if you have any \bf{multiplication.}}\\\text{ We have it, so that is our next step.}`

`\text{3(9) = 27}`

`\text{2(-1) = -1}`

`\text{Our new equation is: 27 - (-2) - 12}`

`\text{Fourthly, let's check to see if we have any\bf{ division}.}\text{ We don't have}\\\text{ any so move on to the next  on which is \bf{addition.}}\\\text{We don't have any of that either. Move on to the last part of it, which is}}\\\text{\bf{subtraction.}}\text{ We have that one. So let's use it for our next step. }`

`\text{27 - (-2) - 12}`

`\text{27 - (-2) = 27 + 2 = 29}`

`\text{29 - 12 = \bf{17}}`

`\boxed{\boxed{\bf{Answer: 17}}}\checkmark`

`\text{Good luck on your assignment and enjoy your day!}`

~
`\frak{LoveYourselfFirst:)}`