Question

If the interplanar distance in the crystal is 287 pm , and the angle of maximum reflection is found to be 7.29 ∘, what is the wavelength of the x-ray beam? (Assume n=1.)

Answer 1

Answer:
`\lambda =72.83 pm`

Step-by-step explanation:

Given

Interplanar distance
`\left ( d\right )=287 pm`

Maximum angle of reflection=
`7.29^(\circ)`

By Bragg's law

d=
`(\lambda )/(2sin\theta)`

Where
`\lambda`=wavelength of x-ray beam

`287* 10^(-12)=(\lambda )/(2sin\left ( \theta\right ))`

`\lambda =287* 10^(-12)* 2* sin\left ( 7.29\right )`

`\lambda =72.83 pm`

Answer 2

72.83 pico meter

Step-by-step explanation:

As per Brags equation :

nλ=2dsinθ

now n=1

θ = 7.29

d= 287 pm

λ = 2dsinθ / n

= 72.83 pico meter