Question

2. A rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μC. Determine the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod.

Answer 1

The magnitude and direction of the net electric field produced by the charged rod can be calculated using the equation E = k * Q * d / (d^2 + L/2^2)^(3/2). The direction of the electric field will be towards the negative charge on the rod, which is the left side of the rod.

Step-by-step explanation:

The electric field produced by a uniformly charged rod at a point along its axis can be calculated using the equation:

E = k * Q * d / (d^2 + L/2^2)^(3/2)

Where:
E is the magnitude of the electric field
k is Coulomb's constant
Q is the total charge on the rod
d is the distance between the point and the center of the rod
L is the length of the rod

In this case, we have:
Q = -22.0 μC
d = 36.0 cm = 0.36 m
L = 14.0 cm = 0.14 m

Plugging in these values, we can calculate the magnitude of the electric field.

The direction of the electric field will be towards the negative charge on the rod, which is the left side of the rod.