Answer:
yes.
Step-by-step explanation:
distance to run = 1 mile
in time = 12 min
student is left will 500 yd to go in 2 min
maximum acceleration = 0.15 m/s² = 590.22 yard/min
1 mile=1760 yards
distance covered 1760-500=1260 yards
speed of the student = 1260/10 = 126 yr/minute
we know
![s= ut + (1)/(2)at^2\\s= 126* 2 + (1)/(2)* 590.22* 2^2\\s = 1,432 yrd](https://img.qammunity.org/2020/formulas/physics/high-school/2nimwujhubua3yuphu0pcw6fy3dqpfzw3t.png)
when the student accelerate at 0.15 m/s² he can easily cover 500 yrd in 2
minutes.