Question

A wire in the form of a circle of diameter 35cm

is bent to form a rectangle whose length is twice
its breadth. Find the area of the rectangle

Answer 1

The wire length = 35*pi

Rectangle length = 35/3*pi

Rectangle breadth = 35/6*pi

Answer: Rectangle area = (35/6*pi)(35/3*pi) = 68.05555555555555555554*pi*pi = about 671.00055555555555555543

round to 671

Answer 2

`Area=671.7cm^2`

Explanation:

This means that the perimeter of the rectangle formed is equal to the circumference of the circle

`Circumference=\pi d\\\\Circumference=35\pi`

Let the length of the rectangle be a and the breadth be b.

`a=2b\\\\Perimeter=35\pi \\\\2a+2b=35\pi \\\\2(2b)+2b=35\pi \\\\6b=35\pi \\\\b=(35\pi )/(6)\\\\Area=a* b\\\\Area=2b* b\\\\Area=2b^2\\\\Area=2* ((35\pi )/(6))^2\\\\Area=671.7cm^2`