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For isosceles trapezoid ABCD, find the length of the median and m∠A

For isosceles trapezoid ABCD, find the length of the median and m∠A-example-1
User Farihah
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2 Answers

3 votes

Answer:

The length of the median is 10, and the measure of the angle ∡A is 68°.

Explanation:

Let us start by the median. Recall that the median of a trapezoid is the segment that joins the midpoints of the non-parallel sides. In this case, the median will join the midpoints of the segments DA and CB. The length of the median of a trapezoid can be easily calculated by the formula


m=(B+b)/(2)

where
m stands for the median,
B for the larger of the parallel sides, and
b for the shorter one. In this particular case
B=AB and
b=DC. Thus,


m=(AB+DC)/(2) = (15+5)/(2) = 10.

Finally, recall that one of the main properties of isosceles trapezoid is that the angles adjacent to the parallel sides are equal. Then, as ∡B=68°, we conclude that ∡A is 68°.

User Rothloup
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4.3k points
6 votes

Answer:

10

68

Explanation:

The median joins the midpoints of AD and CB. It's formula is 1/2 * (5 + 15) = 10 for its length.

If the trapezoid is isosceles, then <A is the same size as <B

User Marceau
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