Question

Which equation in point-slope form contains the points (2.6) and (-1, 3)?

@ y-2 = 1(x-6)
6 y- 6 = 1(x - 2)
© y-2=-1(x - 6)
@y-6=-1(x - 2)

Answer 1

B. y - 6 = 1(x - 2)

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (2, 6) and (-1, 3).

Substitute:

`m=(3-6)/(-1-2)=(-3)/(-3)=1`

Take the point (2, 6):

`y-6=1(x-2)`