Question

A spinner has 8 equal sectors labeled from 1-8 the spinner is spun twice. what is the probability of getting an even number on the first spin and another even number on the second spin?

answer choices:
1/4
7/8
5/16
3/16

Answer 1

My answer is 1/4

Explanation:

Answer 2

A.
`(1)/(4)`

Explanation:

We have been given that a spinner has 8 equal sectors labeled from 1-8 the spinner is spun twice. We are asked to find the probability of getting an even number on the first spin and another even number on the second spin.

Even number from 1-8 are: 2, 4 , 6, 8

Total numbers: 8

`\text{Probability of getting an even number on 1st spin}=(4)/(8)\\\\\text{Probability of getting an even number on 1st spin}=(1)/(2)`

Since spinning of the spinner is independent event, so probability of getting an even number on both spins will be probability of getting an even number on 1st spin times probability of getting an even number 2nd time.

`\text{Probability of getting an even number on 2nd spin}=(4)/(8)\\\\\text{Probability of getting an even number on 2nd spin}=(1)/(2)`

`\text{Probability of getting an even number on both spins}=(1)/(2)* (1)/(2)}\\\\\text{Probability of getting an even number on both spins}=(1)/(4)`

Therefore, option A is the correct choice.