Question

16 individuals in a population of 100 are homozygous recessive for a particular trait (A or a). What percent of the alleles in that population are dominant?

Answer 1

36 individuals

Step-by-step explanation:

In a 100 persons population, 16 represent the 16% of the total or 0.16 This is the percent of recessive alleles.

You know the formulas
`p^(2) +2pq+q^(2) =1` and
`p+q=1`

Where
`q^(2)` is the percent of recessive alleles and
`p^(2)` is the percent of dominant alleles.

If
`q^(2) =0.16` then
`q=√(0.16)=0.4`

and because
`p+q=1`,
`p+0.4=1` then
`p=0.6` and
`p^(2)=0.36`

The percent of dominant alleles in this population is 0.36 or 36%, wich means 36 individuals.