Question

Simplify the expression.
3y2 – 2y[4y - Y(y– 3)] – [2y(y + 1)-3y(y^2-1)] =​

Answer 1

`5y^(3) -13y^(2) -5y`

Explanation:

`3y^(2) -2y[4y - y(y-3)] - [2y(y + 1)-3y(y^(2) -1)] \\\\3y^(2) -2y[4y - y^(2) +3y] - [2y^(2) +2y- 3y^(3)+3y] \\\\3y^(2)- 8y^(2)+2y^(3)- 6y^(2)- 2y^(2)- 2y+3y^(3)- 3y\\\\5y^(3)- 13y^(2)- 5y`