Final answer:
To calculate the mass of water that can be vaporized using 2000 kJ of energy, the latent heat of vaporization formula Q = m x Lv is used. The latent heat of vaporization of water is 2250 kJ/kg.
Step-by-step explanation:
The student asked about the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The provided latent heat of vaporization of water is 2.25 x 106 J kg-1, which is the same as 2250 kJ/kg. To find the mass, you can use the energy equation for phase change which is Q = m x Lv, where Q is the amount of energy (in joules), m is the mass (in kilograms), and Lv is the latent heat of vaporization (in J/kg).