Question

Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle and it has a length of 3 and a width of x-2 .Find the size of the area that was not painted

Help me please

Answer 1

The area that was not painted is
`(2x^(2)-6x+6)\ units^(2)`

Explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

`A=LW`

In this problem we have

`L=2x-3`

`W=x`

substitute

`A=(2x-3)x\\A=(2x^(2)-3x)\ units^(2)`

step 2

Find the area that was painted

`A=(3)(x-2)\\A=(3x-6)\ units^(2)`

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

`A=(2x^(2)-3x)-(3x-6)=(2x^(2)-6x+6)\ units^(2)`