Question

Translate into an algebraic expression: n−1 increased by 110%

Answer 1

Part 1) The algebraic expression is equal to
`1.10(n-1)` or
`1.10n-1.10`

Part 2) The algebraic expression is equal to
`(1.10)/(n)`

Explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

`1.10(n-1)`

Distributed

`1.10n-1.10`

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

`n^(-1)=(1)/(n)`

so

`1.10(n^(-1))=1.10(1)/(n)=(1.10)/(n)`