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Solve: 16x^2 − 80 = 0 using the quadratic formula

Round the answer to the nearest hundredth.


x = −0.45 and x = 0.45
x = −2.24 and x = 2.24
x = −8.94 and x = 8.94
x = −9.80 and x = 9.80

2 Answers

1 vote

Answer:

B

Explanation:

Using the quadratic formula with

a = 16, b = 0 and c = - 80, then

x = ( 0 ±
√(0-(4(16)(-80)) / 32

= ±
(√(5120) )/(32)

x = -
(√(5120) )/(32) , x =
(√(5120) )/(32)

x = - 2.24, x = 2.24 ( to the nearest hundredth )

User Stefan Neubig
by
5.0k points
4 votes

For this case we have the following quadratic equation:


16x ^ 2-80 = 0

Applying the quadratic formula we have:


x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Where:


a = 16\\b = 0\\c = -80

Substituting we have:


x = \frac {-0 \pm \sqrt {0 ^ 2-4 (16) (- 80)}} {2 (16)}\\x = \frac {\pm \sqrt {4 (16) (80)}} {32}\\x = \frac {\pm \sqrt {5120}} {32}\\x = \frac {\pm71.55} {32}

We have two roots:
x_ {1} = \frac {-71.55} {32} = - 2.24\\x_ {2} = \frac {71.55} {32} = 2.24

Answer:

Option B

User Shinese
by
5.0k points