Answer:
The probability that point falls in the white area is 2/3 or 0.667
Explanation:
Consider the provided figure.
As we know there are 360 degrees in a circle.
The diameter divides the circle in two equal half 180° each.
The angle measure of white part in upper half is 180°-60°-60°=60°
The total angle measure of white part in the provided figure is: 180°+60°=240°
Now we need to find the probability that a random selected point falls in the white area
![Probability=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pm6ozbg1oyv41iumpmobyaws0hjkvt0dbd.png)
Substitute Number of favorable outcomes=240° and Total number of outcomes = 360° in the above formula.
![Probability=(240)/(360)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fadaouajdktc7g45vcyln8oonqr7qzrspj.png)
![Probability=(2)/(3)\ \text{or}\ 0.667](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lf3wvrjrpgnhte2438s3dk8kew86afnap0.png)
Hence, the probability that point falls in the white area is 2/3 or 0.667