Question

A ball is dropped to the ground from a height of 100 meters. It rebounds to a height of 50 meters after that first bounce and 25 meters after the second bounce. How high will it rebound on the seventh bounce?

Answer 1

0.78125 m

Explanation:

First term of this geometric series is 50 m, and the common ratio is 1/2.

Thus, a(n) = (50 m)(1/2)^(n-1)

After the 7th bounce, the ball will reach a height of a(7) = (50 m)(1/2)^(7 - 1), or

a(7) = 50 / (2^6) m = 0.78125 m