Question

A centrifuge in a medical laboratory rotates at an angular speed of 3500 rev/min. When switched off, it rotates 46.0 times before coming to rest. Find the constant angular acceleration of the centrifuge.

Answer 1

The angular acceleration of the centrifuge is -231.74 rad/s².

Step-by-step explanation:

Given that,

Angular speed = 3500 rev/min = 366 rad/s

We need to calculate the angular displacement

Using formula of angular displacement

`\theta=2\pi n`

Put the value into the formula

`\theta=2\pi*46`

`\theta=289.02\ rad`

We need to calculate the angular acceleration

Using equation of motion

`\omega_(f)^2=\omega_(i)^2+2\alpha\theta`

`\alpha=(\omega_(f)^2-\omega_(i)^2)/(2\theta)`

`\alpha=(0-(366)^2)/(2*289.02)`

`\alpha=-231.74\ rad/s^2`

Hence, The angular acceleration of the centrifuge is -231.74 rad/s².