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a superconducting solenoid is to be designed to generate a magnetic field of 10 t if the solenoid winding has 2000 turns meter what is the required current

User Dplante
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2 Answers

7 votes

Final answer:

To generate a 10 T magnetic field with a solenoid that has 2000 turns per meter, the required current is calculated using the formula B = μ_0 n I, resulting in a required current of approximately 3981.07 A.

Step-by-step explanation:

To design a superconducting solenoid that generates a magnetic field of 10 T (teslas), we need to calculate the current required for a solenoid with a given number of turns per meter. The magnetic field B inside a long solenoid is given by the formula B = μ_0 n I, where μ_0 is the permeability of free space (1.2566370614 × 10-6 T·m/A), n is the number of turns per meter, and I is the current in amperes.

In this case, the solenoid has 2000 turns per meter and we wish to generate 10 T. Plugging in the values, we get:

10 T = (1.2566370614 × 10-6 T·m/A) × 2000 turns/m × I

Solving for I, we find:

I = 10 T / ((1.2566370614 × 10-6 T·m/A) × 2000 turns/m)

Therefore, the required current is I = 3981.07 A (rounded to two decimal places). Thus, to generate a 10 T magnetic field with a solenoid that has 2000 turns per meter, a current of approximately 3981.07 A would be needed.

User Hannes Stoolmann
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6.8k points
1 vote

Answer:

3981 A

Step-by-step explanation:

B = 10 t

n = 2000 per metre

Let the current is i

Use the formula for the magnetic field due to a current carrying solenoid

B = μo n i

10 = 4 x 3.14 x 10^-7 x 2000 x i

i = 3980.9 A = 3981 A

User Mehmetx
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6.6k points