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The lengths of human pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. What is the probability that a pregnancy last at least 300​ days? Round to four decimal places. A. 0.0164 B. 0.9834 C. 0.4834 D. 0.0179

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Answer: A. 0.0164

Explanation:

Given : The lengths of human pregnancies are normally distributed with a mean
\mu=268\text{ days}

Standard deviation :
\sigma=15\text{ days}

Let X be the random variable that represents the length of pregnancy of a randomly selected human .

z-score :
z=(X-\mu)/(\sigma)

For X = 300


z=(300-268)/(15)\approx2.13

Now, the probability that a pregnancy last at least 300​ days will be :-


P(X\geq300)=P(z\geq 2.1333)=1-P(z<2.1333)\\\\=1- 0.9835513=0.0164487\approx0.0164

Hence, the probability that a pregnancy last at least 300​ days =0.0164

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