Question

Steam enters an adiabatic turbine at 5 MPa and 4500C and leaves at a pressure of 1.4 MPa. Determine the work output of the turbine per unit mass of steam, if the process is reversible.

Answer 1

Answer:350.92 KJ/kg

Step-by-step explanation:

Given the process is reversible adiabatic i.e it is isentropic

`P_1=5 MPa`

`T_1=4500 MPa`

`P_2=1.4 MPa`

From steam table

`h_1=3317.03KJ/kg`

For isentropic process
`s_1=s_2`

at
`P_2=1.4 MPa`

`s_2=6.82 KJ/kg-k`

`h_2=2966.11 KJ/kg`

Therefore Work output of the turbine per unit mass of steam is =
`h_1-h_2`

=3317.03-2966.11

=350.92 KJ/kg