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A snack-size bag of M&Ms candies contains 14 red candies, 10 blue, 5 green, 11 brown, 3 orange, and 12 yellow. If a candy is randomly picked from the bag, compute the following. (a) the odds of getting a green M&M (b) the probability of getting a green M&M

User Teller
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2 Answers

6 votes

Final answer:

The odds of getting a green M&M are 5:55, and the probability of getting a green M&M is 5/55 or approximately 0.091 or 9.1%.

Step-by-step explanation:

(a) The odds of getting a green M&M can be calculated by dividing the number of green M&Ms by the total number of M&Ms in the bag. In this case, there are 5 green M&Ms out of a total of 55 M&Ms (14+10+5+11+3+12). So the odds of getting a green M&M are 5:55.

(b) The probability of getting a green M&M can be calculated by dividing the number of green M&Ms by the total number of M&Ms in the bag. In this case, there are 5 green M&Ms out of a total of 55 M&Ms. So the probability of getting a green M&M is 5/55 or approximately 0.091 or 9.1%.

User Sreejith Sree
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6.8k points
1 vote

Answer:

The odds of getting a green M&M is
(1)/(10) and the probability of getting a green M&M is
(1)/(11)

Step-by-step explanation:

Red candies = 14

Blue candies = 10

Green candies = 5

Brown candies = 11

Orange candies = 3

Yellow candies = 12

Total No. of candies = 14+10+5+11+3+12 = 55

(a) the odds of getting a green M&M

Green candies = 5

Total number of candies excluding green or unfavorable = 50

Odds of getting a green M&M =
\frac{\text{favorable outcome}}{\text{Unfavorable outcomes}}

=
(5)/(50)

=
(1)/(10)

(b) the probability of getting a green M&M

Green candies = 5

Total No. of candies = 55

So, the probability of getting a green M&M =
(5)/(55)

=
(1)/(11)

Hence the odds of getting a green M&M is
(1)/(10) and the probability of getting a green M&M is
(1)/(11)

User Lance Roberts
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