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Forty percent of the homes constructed in the Quail Creek area include a security system. Three homes are selected at random: What is the probability all three of the selected homes have a security system

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Answer: 0.064

Explanation:

Binomial probability formula :-


P(X)=^nC_x \ p^x\ (1-p)^(n-x), where P(x) is the probability of getting success in x trials, n is total number of trials and p is the probability of getting succes in each trial.

Given : The proportion of the homes constructed in the Quail Creek area include a security system :
p=0.40

Now, if three homes are selected at random, then the probability all three of the selected homes have a security system is given by :-


P(3)=^3C_3 \ (0.40)^3\ (1-0.40)^(3-3)\\\\=(0.40)^3=0.064

Hence, the probability all three of the selected homes have a security system = 0.064

User PeteAC
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