Answer:
22.65 rad/s
Step-by-step explanation:
m = 7 kg, r = 0.21 m, F = 44 N, d = 0.9 m
Moment of inertia, I = 1/2 mr^2 = 0.5 x 7 x 0.21 x 0.21 = 0.15435 kg m^2
Work done, W = F x d = 44 x 0.9 = 39.6 J
according to the work energy theorem
Change in the kinetic energy of rotation = Work done
1/ 2 x I x ω^2 = W
0.5 x 0.15435 x ω^2 = 39.6
ω^2 = 513.12
ω = 22.65 rad/s