Answer:
(d): 0.7734
Explanation:
Using the normcdf( statistical function built into my old TI 83-Plus calculator, I find that the area under the standard normal curve from the extreme left to the value 69 is 0.2266. Thus, about 0.2266 of students would fail and
1.000-0.2266, or 0.7734 would pass. This corresponds to Answer (d).