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5 votes
Four cash prizes ($5000, $2000, $500 and $250) to be awarded to 4 students selected randomly from 15 students ( 7 from UCF and 8 from UF). In how many ways the prizes can awarded?

User Bharti
by
4.7k points

1 Answer

7 votes

Answer:

32760 ways

Explanation:

There are overall 15 students from which we have to select 4 students at random for the 4 Cash prizes.

i) First Prize can be distributed in
^(15)\textrm{C}_(1) ways .

Also here we know the identity which says that


^(m)\textrm{C}_(1)=m

Hence
^(15)\textrm{C}_(1)=15

Now we are left with 14 students for second prize.

ii) Second prize can be distributed in
^(14)\textrm{C}_(1)=14 ways

Now we are left with 13 students for third prize.

iii) Third prize can be distributed in
^(13)\textrm{C}_(1)=13 ways.

Now we are left with only one prize and which can be distributed among 12 Students

iv) Fourth prize can be distributed in
^(12)\textrm{C}_(1)=12 ways.

Hence total number of ways of distributing 4 prizes among 15 students is


15 * 14* 13* 12

= 32760

User HeadwindFly
by
5.4k points
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