Answer:
32760 ways
Explanation:
There are overall 15 students from which we have to select 4 students at random for the 4 Cash prizes.
i) First Prize can be distributed in
ways .
Also here we know the identity which says that
![^(m)\textrm{C}_(1)=m](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8rwpqdk9q6xyl2bxe1uhvot2uq8o4v5i9.png)
Hence
![^(15)\textrm{C}_(1)=15](https://img.qammunity.org/2020/formulas/mathematics/high-school/f68y3wknf3ug2x30431ynsvzznef1gwrhf.png)
Now we are left with 14 students for second prize.
ii) Second prize can be distributed in
ways
Now we are left with 13 students for third prize.
iii) Third prize can be distributed in
ways.
Now we are left with only one prize and which can be distributed among 12 Students
iv) Fourth prize can be distributed in
ways.
Hence total number of ways of distributing 4 prizes among 15 students is
![15 * 14* 13* 12](https://img.qammunity.org/2020/formulas/mathematics/high-school/2vb724vk6h04yzjc03rgr65w72emky7bfk.png)
= 32760