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The circle below is centered at the point (8,4) and has a radius of length 4 what is the equation

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1 vote

Answer:

wht are da choices

Explanation:

User Beberlei
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\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{8}{ h},\stackrel{4}{ k})\qquad \qquad radius=\stackrel{4}{ r} \\\\[-0.35em] ~\dotfill\\\\ (x-8)^2+(y-4)^2=4^2\implies (x-8)^2+(y-4)^2=16

User Renosis
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