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A car is moving at 30 ft/sec when the brakes are applied. It decelerates at a constant rate of 5 ft/sec2 until it stops. If t = 0 represents the time at which the brakes are applied, how far will it go before stopping?

1 Answer

6 votes

Answer:

The distance traveled by car before stopping is
90\, ft

Step-by-step explanation:

Given

Initial speed of car
u=30\, (ft)/(sec)

Final speed of the car
v=0\, (ft)/(sec)

Acceleration of the car
a=-5\, (ft)/(sec^(2))

Let distance traveled before stopping be s

Using equation of motion


v^(2)=u^(2)+2as

=>
0^(2)=30^(2)+2* (-5)* s

=>
s=90\, ft

Thus the distance traveled by car before stopping is
90\, ft

User Since K Saji
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