Question

The mass of a mass-and-spring system is displaced 10 cm from its equilibrium position and released. A frequency of 4.0 Hz is observed. What frequency would be observed if the mass had been displaced only 5.0 cm and then released?

Answer 1

f = 4.0 Hz

Step-by-step explanation:

The frequency of SHM in spring mass system is given as

`f = (1)/(2\pi) \sqrt{(k)/(m)}`

now we can see that the frequency of SHM of spring mass system depends upon following parameters

1) mass of the object

2) spring constant

So here it does not depends on the displacement of the object from its mean position

So here the frequency will remain the same

So here

f = 4.0 Hz

Answer 2

It will remain same i.e. 4.0 Hz

Step-by-step explanation:

In a mass-and-spring system, the frequency depends upon the mass (m) and the spring constant (k).

`f=(1)/(2\pi)\sqrt{(k)/(m)}`

Since, the frequency does not depend on the initial displacement of the mass, the frequency would remain the same i.e. 4.0 Hz.