Question

Logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. What is the average density of a uniform-diameter log that floats with 29.1 % of its length above water?

Answer 1

Answer to your question is 709 :)

Answer 2

709 kg/m³

Step-by-step explanation:

Applying the expression obtained from Archimedes Principle as:

`\% of\ the\ fraction\ submerged=\frac {\rho_(object)}{\rho_(liquid)}* 100`

Given :

Percentage of the log above water = 29.1%

Percentage of the log of the water submerged = 100-29.1 % = 70.9%

Density of water = 1000 kg/m³

So,

`70.9 \% =\frac {\rho_(object)}{1000}* 100`

The average density of the log = 709 kg/m³