Question

When a charged particle moves at an angle of 25° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 2F?

Answer 1

Answer:57.7

Step-by-step explanation:

Force on a moving charge in a magnetic field is given by

`F=q* V* Bsin\theta`

Where F=Force experienced by charge

q=charge of particle

V=velocity of particle

B=magnetic field

F=qVBsin(25)-------1

`2F=qVBsin(\theta )------2`

Divide (1)&(2)

`(1)/(2)`=
`(sin(25))/(sin(\theta))`

`Sin(\theta )=2* sin(25)`

`\theta =57.7 ^(\circ)`