Question

A 160-kg object and a 460-kg object are separated by 3.40 m.(a) Find the magnitude of the net gravitational force exerted by these objects on a 33.0-kg object placed midway between them.

Answer 1

The net gravitational force exerted by these objects is
`5.712*10^(-8)\ N`

Step-by-step explanation:

Given that,

Mass of another object m = 33.0 kg

Mass M₁ = 160 kg

Mass M₂ = 460 kg

Distance = 3.40 m

We need to calculate the net gravitational force

Using formula,

`F=(GM_(2)m)/(r^2)-(GM_(1)m)/(r^2)`

`F=Gm((M_(2)-M_(1))/(r^2))`

Where, G = gravitational constant

m = mass of another object

`M_(1)`= mass of first object

`M_(2)`= mass of second object

r = distance

Put the value into the formula

`F=6.67*10^(-11)*33.0*(460-160)/((3.40)^2)`

`F=5.712*10^(-8)\ N`

Hence, The net gravitational force exerted by these objects is
`5.712*10^(-8)\ N`