Answer:
5.95 nm to 33.6 nm
Step-by-step explanation:
Energy of a single photon can be written as:
![E = (hc)/(\lambda)](https://img.qammunity.org/2020/formulas/physics/middle-school/nfyr4rsx6mno78r3g5tk3a26r8gp80fbkb.png)
where, h is the Planck's constant, c is the speed of light and λ is the wavelength of light.
Consider the lowest energy of an electron that can break a DNA = 3.45 eV
1 eV = 1.6 ×10⁻¹⁹ J
⇒3.45 eV = 5.52×10⁻¹⁹ J
![E = (hc)/(\lambda)\\ \Rightarrow \lambda = (hc)/(E)= \frac {6.63* 10^(-34) m^2kg/s * 3* 10^8 m/s}{5.52 * 10^(-19) J} = 3.60* 10^(-7) m = 360 nm](https://img.qammunity.org/2020/formulas/physics/college/dct9d2ixrwpbw941x7fspx0yf290mnwnlq.png)
Consider the highest energy of an electron that can break a DNA = 20.9 eV
1 eV = 1.6 ×10⁻¹⁹ J
⇒20.9 eV = 33.4×10⁻¹⁹ J
![E = (hc)/(\lambda)\\ \Rightarrow \lambda = (hc)/(E)= \frac {6.63* 10^(-34) m^2kg/s * 3* 10^8 m/s}{33.4 * 10^(-19) J} = 0.595* 10^(-7) m = 59.5 nm](https://img.qammunity.org/2020/formulas/physics/college/18j1eg20vmfvfah549da4upup562g23xz0.png)